In fig de is parallel to bc if ad x
WebMar 22, 2024 · Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, …
In fig de is parallel to bc if ad x
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WebIn the given fig, DE is parallel to BC and AD = 1 cm, BD = 2 cm. What is the ratio of the area of ∆ABC to the area of ∆ADE? Two polygons of the same number of sides are similar, if … WebJul 3, 2024 · Given : DE BC. AE = 1.8 cm, BD = 7.2 cm and CE = 5.4 cm. To Find : length of side AD Solution : DE BC Apply BPT Basic proportionality Theorem ( Thales Theorem) AD/BD = AE / CE AD = ? BD = 7.2 cm AE = 1.8 cm CE = 5.4 cm => AD/ 7.2 = 1.8/5.4 => AD / 7.2 = 1/3 => AD = 7.2/3 => AD = 2.4 cm length of side AD = 2.4 cm Learn More:
WebIn Fig. 6.11, if DE BC, find the ratio of ar ( ADE) and ar ( DECB) Solution: Given, DE BC We have to find the ratio of ar ( ADE) and ar ( DECB). From the figure, DE = 6 cm BC = 12 cm In ADE and ABC, ∠A = ∠A = common angle By the property of similar triangles, The corresponding angles are equal. ∠ABC = ∠ADE ∠BCA = ∠AED WebMay 16, 2024 · Math Secondary School answered In the given figure DE is parallel to BC. If AD = x DB = x-2 AE = x+2 and EC = x-1 then calculate the value of x. See answers …
WebSolution: As we all know the Basic Proportionality Theorem (B.P.T) or ( Thales Theorem) Two triangles are similar if Their corresponding angles are equal Their corresponding sides are in the same ratio (or proportion) In, ΔABC BC DE In ΔABC and ΔADE ∠ABC = ∠ADE [corresponding angles] ∠ACB = ∠AED [ corresponding angles] ∠A = ∠A common WebPlease find the answer to your question below Since DE is parllel to BC,by basic proportionality theorem (AB/DB)= (AC/EC) (2x/x-3)= (2x+3/x-2)By cross multiplication we get , 2 x^2 - 4x = 2 x^2 - 3x -9 x = 9 Hope it helps Other Related Questions on 10 grade maths Which among the following is true? 1 Answer (s) Available Slope of Y-axis is .....
WebDec 4, 2024 · Class 10 Maths Term 1 Exam, options for the question – In figure, DE BC, AD= 2 cm and BD= 3 cm, then ar( ABC): ar( ADE) is equal to. a) 4 : 25
WebVerified by Toppr Given: AD=x,DB=16,AB=34 and EC=17 DE∥BC Basic Proportionality theorem. which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio. So, by the basic proportionality theorem. DBAD16x16xx= ECAE= 1734=2=32 st martins theatre view from seatsWeb\frac{AD_1}{AD}=\frac{D_1E_1}{DE}=\frac{AE_1}{AE}. \end{align*} Так как третье отношение первого ряда равно первому отношению второго ряда и третье отношение второго ряда равно первому отношению третьего ряда, то ... st martins therme adresseWebMar 17, 2024 · The value of the expression (x − 2) (x + 4) = a) (x 2 − 2 x − 8) b) (x 2 + 2 x − 8) c) (x 2 − 2 x − 4) d) None Q20. If P (x) = x 2 − 6 x + 4, then the value of polynomial at x = − 1 will be a) 10 b) − 1 c) 11 d) None 12 Feb 2024 st martins theatre london seat viewsWebJun 28, 2024 · Solution : Since DE is parallel to BC, according to the basic proportionality theorem, we get: (AB / DB) = (AC / EC) (2x / x-3)= (2x+3 / x-2) 2x (x-2) = (2x+3) (x-3) 2x^2 - 4x = 2x^2 +3x -6x -9 x - 9 = 0 Therefore x = 9 Advertisement bossnaruto276 Step-by-step explanation: your answer is here with step by step Advertisement Advertisement st martins therme anreiseWebSummary: A parallelogram is a quadrilateral with two pairs of parallel sides. The opposite sides of a parallelogram are equal in length, and the opposite angles are equal in measure. In Fig. 8.11, AB DE, AB = DE, AC DF and AC = DF. It is proven that BC EF and BC = EF. st martins theatre london seatsWebIn fig., DE is parallel to BC. find EC. AD 1 If — = — and AE = 1.2 cm, DB 2 [Al 19921 AD 3 In the given figure, DE is parallel to BC. If and 15 cm, find AE. [Al 1994CJ AD 3 In the given figure, DE BC and -. IfAC= 4.8 cm, find AE. DB 5 [CBSE 2003, 1992 C] AD In given A ABC, DE Il BC and DB find AE 3 - If 5.6 cm 5 [CBSE 1995 In figure, DE Il ... st martins theatre west streetWebMar 22, 2024 · Question 7 (Choice - 1) In the given fig. DE ∥ BC, ∠ADE = 70° and ∠BAC = 50°, then angle ∠BCA = ______Since DE ∥ BC ∠ ABC = ∠ ADE ∠ ABC = 70° By Angle sum property of triangle ∠ BAC + ∠ ABC + ∠ BCA = 180° 50° + 70° + ∠ BCA = 180° 120° + ∠ BCA = 180° ∠ BCA = 180° − 120° ∠ BCA = 60° 1/2 marks 1/2 marks Next: Question 7 (Choice - 2) → Ask … st martins therme bar